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In 1910,Morgan did a series of experiments with the fruit fly Drosophila,an organism where females are XX and males are XY.When a mutant male fly with white eyes was crossed with a wild type female with red eyes,none of the F1 progeny had white eyes but 18% of the F2 progeny had white eyes.Unexpectedly,all of these white-eyed F2 flies were males.Based on these results,Morgan concluded that white eyes is caused by a recessive X-linked allele.Suppose Morgan had found that half of the F1 progeny had white eyes but all of these white-eyed F1 flies were females.In this case,a valid hypothesis would be


A) White eyes is caused by a recessive Y-linked allele.
B) White eyes is caused by a dominant Y-linked allele.
C) White eyes is caused by a dominant X-linked allele.
D) White eyes is caused by a dominant autosomal allele.

E) B) and C)
F) A) and D)

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The classic experiments performed by Creighton and McClintock in Maize


A) provided the initial evidence for genetic recombination.
B) provided evidence that genes located on the same chromosome do not assort independently.
C) allowed for the establishment of the first genetic map.
D) provided evidence for the physical exchange of genetic material between homologues.

E) B) and C)
F) A) and D)

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At an autosomal gene locus in humans,the allele for brown eyes is dominant over the allele for blue eyes.At another gene locus,located on the X chromosome,a recessive allele produces colorblindness while the dominant allele produces normal color vision.A heterozygous brown-eyed woman who is a carrier of colorblindness has children with a blue-eyed man who is not colorblind.What is the probability that their first child will be a blue-eyed female who has normal color vision? (Enter the probability as a percent.Enter the number only without the percent sign.For example,enter 100% as 100 and enter 12.5% as 12.5)

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Of the 23 pairs of human chromosomes,22 pairs are homologous and are found in both males and females.These are called ________.


A) bivalents
B) autosomes
C) recombinant chromosomes
D) somatic chromosomes

E) A) and D)
F) None of the above

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In the fruit fly Drosophila,there is a dominant gene for normal wings and its recessive allele for vestigial wings.At another gene locus on the same chromosome,there is a dominant gene for red eyes and its recessive allele for purple eyes.A male that was heterozygous at both gene loci was mated with a female that was homozygous for both recessive alleles and the following results were observed among the offspring: Normal wings and red eyes - 420 Vestigial wings and red eyes - 80 Normal wings and purple eyes - 70 Vestigial wings and purple eyes - 430 According to these data,what is the distance,in centimorgans,between these 2 gene loci? (Enter the number only without the units.For example,100 cM would be entered as 100)

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Allele pairs are most likely to assort independently of one another when


A) they control unrelated traits.
B) they control related traits.
C) they are on the same chromosome.
D) they are sex-linked.
E) they are on different chromosomes.

F) B) and C)
G) A) and E)

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Humans who have lost one copy of an autosome are called


A) haploid.
B) trisomic.
C) bisomic.
D) monosomic.
E) monoploid.

F) A) and C)
G) C) and D)

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A human female with only one X chromosome is said to have a condition called


A) X chromosome inactivation.
B) Angelman syndrome.
C) Turner syndrome.
D) Klinefelter syndrome.
E) Down syndrome.

F) All of the above
G) A) and E)

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In Drosophila,the allele red eyes (bw+) is dominant to the allele for brown eyes (bw) .At another gene locus on the same chromosome,the allele for thin wing veins (hv+) is dominant to the allele for heavy wing veins (hv) .Flies homozygous for bw and hv+ are crossed to flies homozygous for bw+ and hv to obtain doubly heterozygous F1 progeny. -What would be the results of a test cross with the F1 flies?


A) 1 brown eye,thin wing veins: 1 red eye,heavy wing veins
B) 1 brown eye,heavy wing veins: 1 red eye,thin wing veins
C) 1 brown eye,thin wing veins: 2 red eye,thin wing veins: 1 red eye,heavy wing veins
D) 1 brown eye,heavy wing veins: 2 red eye,thin wing veins: 1 red eye,thin wing veins

E) All of the above
F) B) and C)

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________ is a human hereditary disease that is caused by a dominant allele but does not show up in affected individuals until they are in middle age.


A) Cystic fibrosis
B) Sickle cell anemia
C) Tay-Sachs disease
D) Huntington's disease
E) Hemophilia

F) A) and E)
G) B) and C)

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Which of the following animals is a genetic male?


A) bird ZW
B) grasshopper XO
C) honeybee diploid
D) Drosophila XXY

E) B) and C)
F) B) and D)

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Any genetic differences between individuals in a population are called


A) markers.
B) alleles.
C) polymorphisms.
D) SNPs.

E) All of the above
F) A) and C)

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Amniocentesis is a procedure that is normally used


A) to reduce the risk of genetic disease.
B) for gene therapy.
C) to change the sex of the fetus.
D) for diagnosis of genetic disorders.
E) for nourishing the fetus.

F) A) and E)
G) A) and B)

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If you needed to determine the order of genes on a chromosome,you should perform


A) a test cross.
B) a two-point cross.
C) a three-point cross.
D) a SNP test.

E) None of the above
F) A) and D)

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How many Barr bodies does a normal human female contain in each diploid cell?


A) 0
B) 1
C) 2
D) 3

E) None of the above
F) A) and B)

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In Drosophila,dosage compensation is controlled by the male-specific lethal (MSL) complex consisting of MSL proteins and roX RNAs.Based on what you know about dosage compensation,the role of the MSL complex in males would be to


A) double the level of expression of genes on the X chromosome.
B) increase the level of expression of genes on the X chromosome by 50%.
C) decrease the level of expression of genes on the X chromosome by 50%.
D) decrease the level of expression of genes on the X chromosome by 100%.
E) double the level of expression of genes on the Y chromosome.

F) A) and E)
G) B) and D)

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Suppose you are carrying out a series of crosses with an insect where the mechanism of sex determination is unknown.You discover a mutant female with short bristles and decide to cross it with a wild type male that has normal bristles.Half of the F1 progeny have short bristles but all of these short-bristled F1 progeny are males.Based on these results,a valid hypothesis would be


A) Males are ZW,females are ZZ,and short bristles are caused by a dominant allele on the Z chromosome.
B) Males are ZZ,females are ZW,and short bristles are caused by a recessive allele on the Z chromosome.
C) Males are ZZ,females are ZW,and short bristles are caused by a dominant allele on the W chromosome.
D) Males are ZZ,females are ZW,and short bristles are caused by a dominant allele on the Z chromosome.

E) None of the above
F) A) and C)

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Hemophilia is caused by a


A) recessive allele on the X chromosome.
B) dominant allele on the X chromosome.
C) codominant allele on the X chromosome.
D) recessive allele on an autosome.
E) dominant allele on an autosome.

F) All of the above
G) B) and C)

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